For the function is both an inflection point and a local maximum/minimum?
Calculus Volume 1 · 4.5 Derivatives and the Shape of a Graph
Derivatives and the Shape of a Graph: practice problems
32 problems from the book, with its answers. Check your working, or have any of them explained to you on the whiteboard.
Exercises 197
Exercises 199
Exercises 201
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Exercises 207
Exercises 209
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Review Exercises 535
Review Exercises 537
Review Exercises 547
Review Exercises 551
Key terms · 7
- concave down
- if $f$ is differentiable over an interval $I$ and $f'$ is decreasing over $I,$ then $f$ is concave down over $I$
- concave up
- if $f$ is differentiable over an interval $I$ and $f'$ is increasing over $I,$ then $f$ is concave up over $I$
- concavity
- the upward or downward curve of the graph of a function
- concavity test
- suppose $f$ is twice differentiable over an interval $I;$ if $f'' > 0$ over $I,$ then $f$ is concave up over $I;$ if $f'' < 0$ over $I,$ then $f$ is concave down over $I$
- first derivative test
- let $f$ be a continuous function over an interval $I$ containing a critical point $c$ such that $f$ is differentiable over $I$ except possibly at $c;$ if $f'$ changes sign from positive to negative as $x$ increases through $c,$ then $f$ has a local maximum at $c;$ if $f'$ changes sign from negative to positive as $x$ increases through $c,$ then $f$ has a local minimum at $c;$ if $f'$ does not change sign as $x$ increases through $c,$ then $f$ does not have a local extremum at $c$
- inflection point
- if $f$ is continuous at $c$ and $f$ changes concavity at $c,$ the point $(c, f (c))$ is an inflection point of $f$
- second derivative test
- suppose $f' (c) = 0$ and $f''$ is continuous over an interval containing $c;$ if $f'' (c) > 0,$ then $f$ has a local minimum at $c;$ if $f'' (c) < 0,$ then $f$ has a local maximum at $c;$ if $f'' (c) = 0,$ then the test is inconclusive
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