Hey Seo Pilot, I'm Theo! Let's break down this stoichiometry problem together.
We're starting with a solution volume and molarity of hydrochloric acid, and we need the moles and mass of gallium chloride produced.
Looking at part A, how would you find the moles of hydrochloric acid from that volume and concentration?
Boom! Perfect calculation.
Litres cancel neatly, leaving us with moles of HCl.
Now for step two: looking at the coefficients in our balanced reaction, what mole ratio converts HCl to GaCl3?
Nice work! That simplifies to one third, landing right at one point two five moles rounded.
Now the question also asked for the mass of GaCl3. What's the molar mass of GaCl3?
Take a quick look at the periodic table values on the right: what do gallium and those three chlorines add up to?
Spot on! One hundred seventy-six point zero seven grams per mole.
Now for the final stretch: how do we turn our moles of GaCl3 into grams?
What do you get when you multiply those out, keeping significant figures in mind?
Boom, right on the money! Two point two times ten to the second grams matches the book perfectly.
You nailed every single calculation here! What did your original attempt look like that was giving you trouble?